A Train Travelling At Constant Speed Crosses A 96m Long Platform In 1

1.	A Train Travelling At Constant Speed Crosses A 96m Long Platform In 12 Seconds And Another 141m Long Platform In 15 Seconds. The Length Of The Train And It’s Speed Are?
Answer» LET the length of the TRAIN be x metres. =&GT;(96+x)/12=(141+x)/15 => 15x(96 +x) = 12 x (141 + x) => 3x = (1692 -1440) = 252 => X = 84m Speed of the train = 15 m/sec = (15 x 18/5)kmph = 54kmph. Let the length of the train be x metres. =>(96+x)/12=(141+x)/15 => 15x(96 +x) = 12 x (141 + x) => 3x = (1692 -1440) = 252 => X = 84m Speed of the train = 15 m/sec = (15 x 18/5)kmph = 54kmph.

A Train Travelling At Constant Speed Crosses A 96m Long Platform In 12 Seconds And Another 141m Long Platform In 15 Seconds. The Length Of The Train And It’s Speed Are?

Answer»

LET the length of the TRAIN be x metres.

=&GT;(96+x)/12=(141+x)/15

=> 15x(96 +x) = 12 x (141 + x)

=> 3x = (1692 -1440) = 252

=> X = 84m

Speed of the train = 15 m/sec

= (15 x 18/5)kmph = 54kmph.

Let the length of the train be x metres.

=>(96+x)/12=(141+x)/15

=> 15x(96 +x) = 12 x (141 + x)

=> 3x = (1692 -1440) = 252

=> X = 84m

Speed of the train = 15 m/sec

= (15 x 18/5)kmph = 54kmph.