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A transistor is operated in common emitter configuration at `V_(c)=2 V` such that a change in the base current from `100 muA` to `300 muA` produces a change in the collector current from `10 mA` to `20 mA`. The current gain isA. `75`B. `100`C. `25`D. `50` |
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Answer» Correct Answer - D `beta=(DeltaI_(C))/(DeltaI_(B))=((20-10)mA)/((300-100)mA)=(10xx10^(-3))/(200xx10^(-6))=50` |
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