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A transmitter supplies `9 kw` to the aerial when unmodulated. The power radiated when modulation index is `60 %`, isA. `9.72 kw`B. `9 kw`C. `5.4 kw`D. `10.62 kw` |
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Answer» Correct Answer - D `P_(t) = P_(c )(1 +(m^(2))/(2)) = 9 (1 + ((0.6)^(2))/(2)) = 9 [1 + (0.36)/(2)]` `= 9 [1 + 0.18] = 9 [1.18] = 10.62 kw` |
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