InterviewSolution
Saved Bookmarks
| 1. |
A transmitter supplies `9kW` to the aerial when unmodulated. The power radiated when modulated to `40%` isA. `5 kW`B. `9.72 kW`C. `10 kW`D. `12 kW` |
|
Answer» Correct Answer - B (`2`) `P_(t)=P_(c)[1+(m^(2))/(2)]=9[1+((0.4)^(2))/(2)]` `=9[1+(0.16)/(2)]` (`Qm=40%=0.4`) `=9(1.08)=9.72 kW` |
|