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A transverse sinusoidal wave of amplitude `a`, wavelength `lambda` and frequency `f` is travelling on a stretched string. The maximum speed of any point in the string is `v//10`, where `v` is the speed of propagation of the wave. If `a = 10^(-3)m` and `v = 10ms^(-1)`, then `lambda` and `f` are given byA. `lambda=2pixx10^(-2)m`B. `lambda=10^(-3)m`C. `f 10^(3)//(2pi)Hz`D. `f=10^(4) Hz` |
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Answer» Correct Answer - a., c., d. `v_(max)=aomega=a(2pif)` Given that `a(2pif)=(v)/(10)=(10)/(10)=1` `f=(1)/(2pia)=(10^(3)/(2pi)Hz` As `v=flambda` or `lambda=(v)/(f)=(10)/(10^(3)//(2pi)=2pixx10^(2)m` |
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