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A particle on a stretched string supporting a travelling wave, takess `5.0 ms` to move from its mean position to the extreme position. The distance between two consecutive particle, which are at their mean position, is `3.0 cm`. Find the wave speed `(in m//s)`. |
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Answer» Time period `T=4xx5 ms=20xx10^(-3)=2xx10^(-2)s` Frequency, `f=(1)/(T)=(1)/((2xx10^(--2)))=50 Hz` `lambda=2xx3 cm=6 cm` wave speed: `v=lambdaf=0.06xx50=3 m//s` |
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