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A transverse wave is produced on a stretched string 0.9 m long and fixed at its ends. Find the speed of the transverse wave, when the string vibrates while emitting second overtone of frequency 324 Hz. |
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Answer» Data : L = 0.9 m, n (second overtone) = 324 Hz For the second overtone of a vibrating string, λ = \(\frac23L\) The speed of the transverse wave formed on the string, v = nλ ∴ v = n × \(\frac23L\) = 324 × \(\frac23\) x 0.9 = 324 × 0.6 = 194.4 m/s |
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