A transverse wave is represented by y = Asin(omegat - kx). For what value of the wavelength is the wave velocity equal to the maximum particle velocity ?

A transverse wave is represented by y = Asin(omegat - kx). For what va

1.	A transverse wave is represented by y = Asin(omegat - kx). For what value of the wavelength is the wave velocity equal to the maximum particle velocity ?
Answer» `(PIA)/(2)` `piA` `2piA` `A` SOLUTION :Here y = `A sin(omega t -kx),` Moreover `V _(max) =v ` (GIVEN) `therefore A omega = (omega )/(k)` `therefore A = (1)/( k ) = (lamda )/( 2pi // lamda) = (lamda)/( 2pi )` `therefore lamda = 2pi A`