1.

A transverse wave of amplitude 0.5m, wavelength 1m and frequency 2Hz is propagating in a string in the negative x direction. The equation of this wave is ……………… .

Answer»

y = 0.5 sin `(2pi x - 4PI t)`
`y = 0.5 sin (2pi x + 4pi t)`
`y = 0.5 sin (pi x - 2pi t)`
`y = 0.5 cos (kx - 2pi t)`

Solution :`y = A sin (kx + omega t)`
Here `A = 0.5` m
`K = (2pi)/(lambda) = (2pi)/(1) = 2 pi m^(-1) , omega = 2pi f = 4pi ` rad/s
`implies y = 0.5 sin (2pi x + 4 pi t)`


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