A transverse wave propagating on a stretched string of linear density 3 xx 10^(-4) kg m^(-1) is represented by the equation y = 0.2 sin (1.5 x + 60 t) Where x is in metres and t is in seconds . The tension in the string (in newtons) is :

A transverse wave propagating on a stretched string of linear density

1.	A transverse wave propagating on a stretched string of linear density 3 xx 10^(-4) kg m^(-1) is represented by the equation y = 0.2 sin (1.5 x + 60 t) Where x is in metres and t is in seconds . The tension in the string (in newtons) is :
Answer» 0.24 0.48 `1.20` `1.80` SOLUTION :`V = SQRT((T)/(m)) = (omega)/(k) IMPLIES T = ((omega)/(k))^(2) m = ((60)/(1.5))^(2) xx 3 xx 10^(-4) = 0.48` N