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A travelling wave has the frequency `upsilon` and the particle displacement amplitude `A`. For the wave the particle velocity amplitude is ………………… and the particle acceleration amplitude is …………………….. |
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Answer» If `y = A sin(omegat - kx)`, displacement amplitude `= A` (Maximum displacement) Particle velocity, `v = (dy)/(dt) = A omega cos(omega t - kx)` Therefore, velocity amplitude `= A omega = A(2 pi v)` (Maximum velocity) Particle acceleration, `A c c = (dv)/(dt) = - A omega^(2) sin(omega tau - kx)` Therefore, acceleration(maximum acceleration) amplitude `= A omega^(2) = A(2 pi v)^(2)`. |
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