InterviewSolution
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InterviewSolution
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A travelling wave represented by `y=Asin (omegat-kx)` is superimposed on another wave represented by `y=Asin(omegat+kx).` The resultant isA. A standing wave having nodes at `x=(n+(1)/(2))(lamda)/(2),n=0,1,2`B. A wave travelling along + x directionC. A wave travelling along -x directionD. A standing wave having nodes at `x = (n lamda)/(2) , n=0,1,2` |
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Answer» Correct Answer - A `y_(1)=Asin(wt-kx)&y_(2)=Asin(wt-kx)` By superposition principle `y = y_(1) +y_(2)` `=A sin (wt-kx)+A sin (wt +kx)` `=2A sin wt cos kx` Amplitude = 2A cos kx At nodes displacement is minimum `2A coc kx =0 rArr cos kx =0` `kx = (2n+1) (pi)/(2) rArr (2pi)/(2)x=(2n+1)(pi)/(2)` `x =(2n+1)(pi)/(4)` where `n =0,1,2` |
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