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A car has two horns having a difference in frequency of 180 Hz. The car is approaching a stationary observer with a speed of `60 ms^(-1)`. Calculate the difference in frequencies of the notes as heard by the observer, If velocity of sound in air is `330 ms^(-1)`. |
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Answer» Correct Answer - `220 Hz` `Delta f=f_(0)((v)/(v-v_(S)))=180((300)/(330-60))=220Hz` |
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