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A triangle is formed by the lines whose combined equation is given by `(x-y-4)(xy-2x-y+2)=0` The equation of its circumcircle is: |
Answer» `(x-y-4)(xy-2x-y+2)=0` `x-y=4` `xy-2x-y+2=0` `x(y-2)-1(y-2)=0` `(x-1)(y-2)=0` AB is perpendicular to BC AC is diameter of the circle. `(x-1)(x-2)+(y-3)(y-2)=0` `x^2-3x+2+y^2-5y+6=0` `x^2+y^2-3x-5y+8=0`. |
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