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A trolley, while going down an inclined plane, has an acceleration of `2 cm//s^(2)` starting from rest. What will be its velocity `3 s` after the start ? |
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Answer» Here, `" "` Initial velocity, `u=0` Final velocity, `v=?" "` (To be calculated) Acceleration, `a=2" cm "s^(-2)` And, `" "` Time, `t= 3 s` Now, `" "v= u+at` So, `" " v= 0+2xx3` or `" " v= 6" cm "s^(-1)` Thus, the velocity of trolley after 3 s will be 6 centimetres per second. |
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