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A truck moving at `15m//s` has KE of `4.2xx10^5` J (a) what is the mass of the truck ? (b) By what multiplicative factor does the kinetic energy of the truck increases if its speed is doubled? |
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Answer» (a) `K = (1)/(2) m upsilon^2, m = (2K)/(upsilon^2) = (24.2xx10^5J)/((15m^2) )= 3733 kg` (b) Kinetic energy depends on the speed squared, and hence doubling the speed increases the kinetic energy by a factor of four. |
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