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A truck of mass 1000 kg accelerates uniformly from rest to a velocity of 15 ms'in 5 seconds. Calculate (i) its acceleration (ii) its gain in KE and (iii) average power of the engine during this period, neglect friction |
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Answer» Solution :(i) `a=(V-u)/t=3m/s^(2)` (II) `"Gain in K.E."=1/2m(v^(2)-u^(2))=1.125xx10^(5)J` (iii) `p=W/t=225000W` |
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