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A truck of mass `M` is moved under a force `F`. If the truck is then loaded with an object equal to the mass of the truck and the driving force is halved, then how does the acceleration change? |
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Answer» As mass of loaded truck becomes 2 times and driving force is halved, therefore, from `F=ma, a=F/m=(1//2 "time")/(2 "time")=1/4` time i.e., acceleration would become `1/4th` |
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