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A truck weighing 1000 kg is moving with velocity of 50 km/h on smooth horizontal roads. A mass of 250 kg is dropped into it. The velocity with which it moves now is –(a) 12.5 km/h (b) 20 km/h (c) 40 km/h (d) 50 km/h |
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Answer» (c) 40 km/h According to law of conservation of linear momentum m2 v2 = (m1 + m2 )v2 v2 = \(\frac{m_1v_1}{m_1 + m_2}\) = \(\frac{1000 \times 50}{1250}\) = 40 km/h |
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