1.

A tube of length closed at one end is lowered into a tank of mercury to a depth H Mercury rises to a height into the tube. It the mercury barometer stands at then

Answer»

`H=(2H-h))(H-h)`
`H=[(2H-h)(H-h)]^((1)/(2))`
`H=(2H-h)(H+h)`
`H=[(2H-h)(H-h)]^(3//2)`

ANSWER :B


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