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A tube of sugar solution 20 cm long is placed between crossed nicols and illuminated with light of wavelength `6xx10^(-5)` cm If the optical rotation produced is `13^(@)` and the specific rotation is `65^(@)` determine the strength of the solutionA. `0.1g//cc`B. `0.2g//cc`C. `0.9g//cc`D. `1.0g//cc` |
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Answer» Correct Answer - A The specific totation `alpha` of a solution is given by `alpha=(theta)/(lxxC)` where `theta` is the optical rotation in degrees, I is the length of the tube in dicimeter and c the strength of the solution in `gm//cc` `therefore C=(theta)/(Ixxalpha)` Here `theta =13^(@),I=20cm=2.0 decimeter and alpha=65^(@)` `therefore c=(13^(@))/(2xx65^(@))=0.1g//cc` |
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