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A tube open at both ends has length 47 cm. Calculate the fundamental frequency of air column.(Neglect end correction. Speed of sound in air is 3.3 x102 m/s). |
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Answer» Given : L = 47 cm = 47 x 10-2 m, v = 3.3 x 102 m/s To find : Fundamental frequency of air column (n) Formula: n = \(\frac{v}{2L}\) Calculation: From formula, n = \(\frac{3.3\times10^2}{2\times47\times10^{-2}}\) = \(\frac{330}{94}\times10^2\) = antilog [log(330) – log(94)] x 102 = antilog[2.5185 – 1.9731] x 102 = antilog[0.5454] x 102 = 3.512 x 102 ∴ n = 351.2 Hz Ans: The fundamental frequency of air column is 351.2 Hz. |
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