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A tunnel is dug along the diameter of the earth. The gravitational force on particle of mass m placed in the tunnel at a distance 'x' from the centre. |
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Answer» Solution :MASS of earth `M = (4)/(3)pi R^(3) rho` Mass of IMAGINARY sphere, having radius x, `M^(1) = (4)/(3)pi x^(3) rho` (or) `(M^(1))/(M) = (x^(3))/(R^(3))` `therefore` GRAVITATIONAL force on .m. due to `M_(1)` `F = (GM^(1)m)/(x^(2))` (or) `F = (Gm)/(x^(2))((x^(3))/(R^(3))M) = (GMmx)/(R^(3))`
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