A turbine generates 1.64 MW. Assuming the efficiency to be 80% and head of water used 1663 m, calculate the rate of flow of water.

A turbine generates 1.64 MW. Assuming the efficiency to be 80% and hea

1.	A turbine generates 1.64 MW. Assuming the efficiency to be 80% and head of water used 1663 m, calculate the rate of flow of water.
Answer» SOLUTION :`P=1.64xx10^(6)W` Gravitational head = 1663 m `eta=80%` available POWER = `0.8xx1.64xx10^(6)W` i.e. `P'=1.312xx10^(6)W=(("mgh"))/(t)` i.e. `(m)/(t)=(1.312xx10^(6))/(gh)=(1.312xx10^(6))/(9.8xx1663)` `(m)/(t)=80.5kgs^(-1)or(V)/(t)=((80.5)/(10^(3)))m^(3)s^(-1)` i.e. `(V)/(t)=80.5xx10^(-3)m^(3)s^(-1)=80.5" LITRES "s^(-1)`.