InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A two-digit number is made of two consecutive digits such that the sum of their squares is 4less than the number. Find the two-digit number. |
|
Answer» Let one place digit be x and ten place digit be (x + 1) of two digit number. Then,Number = 10*(x + 1) + x = 11x + 10 As per given conditionx^2 + (x + 1)^2 = (11x + 10) - 4x^2 + x^2 + 1 + 2x = 11x + 62x^2 - 9x - 5 = 02x^2 - 10x + x - 5 = 02x(x - 5) + 1(x - 5) = 0(2x + 1)(x - 5) = 0x = - 1/2, 5 Negative value not possible Therefore,Two digit number= 11*5 + 10= 65 |
|