A U tube is held such that the radius of one limb is r, and that of other is r_(2)(r_(2)gtr_(1)). A liquid of surface tension S, density rho and angle of contact zero is taken in the U tube. Then difference in the levels of the liquid in the two limbs is,

A U tube is held such that the radius of one limb is r, and that of ot

1.	A U tube is held such that the radius of one limb is r, and that of other is r_(2)(r_(2)gtr_(1)). A liquid of surface tension S, density rho and angle of contact zero is taken in the U tube. Then difference in the levels of the liquid in the two limbs is,
Answer» Solution :PRESSURE at BOTTOM of Ist limb `p_(1)=h_(1)rhog+p_(0)-(2S)/r_(1)` Pressure at bottom of 2ND limb `p_(2)=h_(2)rhog+p_(0)-(2S)/r_(2)` Difference in the LEVELS is `(h_(1)-h_(2))=(2S)/(rhog)(1/r_(1)-1/r_(2))`