[A] underset("Catalyst")overset(H_2//"Lindler's")larr CH_3 - C -= C-CH_3 underset(liq. NH_3)overset(Na " in ")to [B] ,[A] and [B] respectively are

[A] underset("Catalyst")overset(H_2//"Lindler's")larr CH_3 - C -= C-CH

1.	[A] underset("Catalyst")overset(H_2//"Lindler's")larr CH_3 - C -= C-CH_3 underset(liq. NH_3)overset(Na " in ")to [B] ,[A] and [B] respectively are
Answer» <html><body><p>cis, <a href="https://interviewquestions.tuteehub.com/tag/trans-1425477" style="font-weight:bold;" target="_blank" title="Click to know more about TRANS">TRANS</a> -2-butene <br/>both trans-2-butene<br/>trans, cis-2-butene<br/>both cis-2-butene</p>Solution :Reduction of 2-butyne with <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>, in <a href="https://interviewquestions.tuteehub.com/tag/presence-25557" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENCE">PRESENCE</a> of Lindlar.s catalyst `(pd-BaSO_4)` gives cis-2-butene while with Na/liq.`NH_3` (<a href="https://interviewquestions.tuteehub.com/tag/brich-7312121" style="font-weight:bold;" target="_blank" title="Click to know more about BRICH">BRICH</a> reduction) gives trans -2-butene</body></html>