[A] underset("Catalyst")overset(H_2//"Lindler's")larr CH_3 - C -= C-CH_3 underset(liq. NH_3)overset(Na " in ")to [B] ,[A] and [B] respectively are

[A] underset("Catalyst")overset(H_2//"Lindler's")larr CH_3 - C -= C-CH

1.	[A] underset("Catalyst")overset(H_2//"Lindler's")larr CH_3 - C -= C-CH_3 underset(liq. NH_3)overset(Na " in ")to [B] ,[A] and [B] respectively are
Answer» cis, TRANS -2-butene both trans-2-butene trans, cis-2-butene both cis-2-butene Solution :Reduction of 2-butyne with H, in PRESENCE of Lindlar.s catalyst `(pd-BaSO_4)` gives cis-2-butene while with Na/liq.`NH_3` (BRICH reduction) gives trans -2-butene