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A uniform ball of radius `R` rolls without slipping between the rails such that the horizontal distance is `sqrt(3)R` between the two contact points of te rails of the ball. Figure (a) shows front view of the ball and figure (b) shows the side view of the ball. `v_(CM)` is the velocity of centre of mass of the ball and `omega` is the angular velocity of the ball after rolling down a distance `2h` along the incline then A. `V_(CM)=omegaR`B. `V_(CM)=omega R/2`C. `V_(CM)=sqrt((10gh)/13)`D. `V_(CM)=sqrt((10 gh)/7)` |
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Answer» Correct Answer - B::C `v_(CM)=omega sqrt(R^(2)-(3R^(2))/4)=omega R/2` (from pure rolling) `mgh=1/2mv_(cm)^(2)+1/2 2/5 mR^(2)omega^(2)` (from conservation of energy) `:.v_(CM)=sqrt((10gh)/13)` |
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