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A uniform block of mass M and dimensions as shown in the figure is placed on a rough horizontal surface and given a velocity `V_(0)` to the right. A is a point on the surface to the left of the block. (a) Write the angular momentum of the block about point A just after it begins to move (b) Due to friction the block stops. What happened to its angular momentum about point A? Which torque is responsible for change in angular momentum of the block? |
Answer» Correct Answer - (a) `(MV_(0)b)/(2)` (b) Normal reaction produces a torque |
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