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A uniform chain of length 2L is hanging in equilibrium position, if end `B` is given a slightly downward displacement the imbalance causes an acceleration. Here pullley is small and smooth & string is inextensible The velocity `v` of the string when it slips out of the pulley (height of pulley from floor`gt2L`)A. `sqrt((gL)/(2))`B. `sqrt(2gL)`C. `sqrt(gL)`D. none of these |
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Answer» Correct Answer - C `v(dv)/(dx)=(x)/(L)g" "rArrint_(0)^(v)"v dv"=(g)/(L)int_(0)^(L)"x dx"rArrvsqrt(gL)` |
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