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A uniform chain of mass M = 4.8 kg hangs in vertical plane as shown in the fig. (a) Show that horizontal component of tension is same throughout the chain. (b) Find tension in the chain at point P where the chain makes an angle `theta = 15^(@)` with horizontal. (c) Find mass of segment AP of the chain. [Take `g = 10 m//s^(2), "cos" 15^(@) = 0.96 , "sin"15^(@) = 0.25`] |
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Answer» Correct Answer - (b) `T_(P) = 21. 65 N` (c) 3.05 kg |
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