InterviewSolution
Saved Bookmarks
| 1. |
A uniform chain of mass m and length l is lying on a table with l/4 of its length hanging freely from the edge of the table. The amount of work done in dragging the chain on the table completely is :–(a) mgl/4(b) mgl/8(c) mgl/32(d) mgl/16 |
|
Answer» Correct option (c) mgl/32 Explanation: Mass of (l/4) length of the chain = m/4 The weight of this part of the chain acts as its CG which is at a distance (L/8) from the edge of the table. Work done = (m/8) g (L/8) = mgl/32 |
|