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A uniform circular disc of mass m is set rolling on a smooth horizontal table with a uniform linear velocity v. Find the total K.E., of the disc. |
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Answer» Solution :M.I. of th DISC about its own axios, Formula, `I=1/2 MR^(2)` As `v=R omega: omega^(2)=(v^(2))/(r^(2))` Rotational K.E. `=1/2 I omega^(2)` `=1/2xx1/2mr^(2)XX(v^(2))/(r^(2))=1/4 mv^(2)` Translational K.E. `=1/2mv^(2)` Total K.E. `=` Rotaltional K.E.+Translational K.E `=1/4mv^(2)+1/2 mv^(2)` `=3/4 mv^(2)` |
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