1.

A uniform circular disc of mass m is set rolling on a smooth horizontal table with a uniform linear velocity v. Find the total K.E., of the disc.

Answer»

Solution :M.I. of th DISC about its own axios,
Formula, `I=1/2 MR^(2)`
As `v=R omega: omega^(2)=(v^(2))/(r^(2))`
Rotational K.E. `=1/2 I omega^(2)`
`=1/2xx1/2mr^(2)XX(v^(2))/(r^(2))=1/4 mv^(2)`
Translational K.E. `=1/2mv^(2)`
Total K.E. `=` Rotaltional K.E.+Translational K.E
`=1/4mv^(2)+1/2 mv^(2)`
`=3/4 mv^(2)`


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