A uniform circular disc of radius 50 cm at is free to turn about an axis which is perpendicular to its plane and passes through its centre. It is subjected to a torque which produces a constant angular acceleration of 2"rad"s^(-2). Its net acceleration is ms^(-2) at the end of 2.0 s is approximately.

A uniform circular disc of radius 50 cm at is free to turn about an ax

1.	A uniform circular disc of radius 50 cm at is free to turn about an axis which is perpendicular to its plane and passes through its centre. It is subjected to a torque which produces a constant angular acceleration of 2"rad"s^(-2). Its net acceleration is ms^(-2) at the end of 2.0 s is approximately.
Answer» 6 6 8 7 Solution :Radius `=R=50 cm =0.5m` ANGULAR accelerastion `alpha=2 "rad"s^(-2)` Initial angular velcocity `omega_(0)=0` `=0.5xx2=1ms^(-2)` `omega=omega_(0)+alphat` At the end of 2 sec, `omega=omega_(0)+alphat` `=0+2xx2=4"rad" s^(-1)` Radial acceleration `a_(r)=omega^(2)r` `a_(4)=(4)^(2)xx0.5=8ms^(-2)` Net acceleration `=sqrt(a_(4)^(2)+a_(t)^(2))` `=sqrt((8)^(2)+(1)^(2))=sqrt(65)` `=8ms^(-2)`