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A uniform circular ring radius 'R' lies in the xy plane with its centre at origin Its moment of inertia about axis lying The XY-plane parallel to X-axis and passing through a point on the Y-axis at a distance Y=2R is I_(1). Its M.I. about axis lying in a plane perpendicular to XY-plane passing through a point on the - axis at a distance x=d is I_(2). I f I_(1)=I_(2), the value of 'd' is |
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Answer» `Rsqrt(7//2)` |
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