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A uniform conducting ring of mass `pi` kg and radius 1 m is kept on smooth horizontal table. A uniform but time varying magnetic field `B = (hat (i) + t^(2) hat (j))T` is present in the region, where t is time in seconds. Resistance of ring is `2 (Omega)`. Then Time (in second) at which ring start toppling isA. `(10)/(pi)sec`B. `(20)/(pi)sec`C. `(5)/(pi)sec`D. `(5)/(pi)sec` |
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Answer» Correct Answer - A `I=(1)/(R)|(dphi)/(dt)|=(1)/(2)pixx1^(2)::2t=pit` The ring will start toppling when `tau_(m)=tau_(g)` `impliesIAB_(x)=mgr` `impliespitxxpixx1^(2)xx1=pixx10xx1` `impliest=(10)/(pi)sec` |
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