1.

A uniform cube of mass m and side a is placed on a frictionless horizontal surface. A vertical force Fis applied to the edge as shown in figure. Match the following (most appropriate choice).

Answer»

Solution :Torque of force about point A is `tau=Fa` (anticlockwise)
Torque of weight mg of cube about point A
`tau_(2)=mg((a)/(2))` (CLOCKWISE)
The cube will not exhibit just rotational MOTION if
`tau_(1)=tau_(2)`
or `F=(mg)/(2)`
Cube will rotate if `tau_(1) gt tau_(2)or F gt (mg)/(2)`
For normal reaction force acting effectively at a DISTANCE `(a)/(3)` from point A, the cube will just rotate if
`mgxx(a)/(3)=Fa`
or `F=(mg)/(3)`
When `F=(mg)/(4) LT (mg)/(3)`, there will be no rotational motion
So, we conclude that
`(a) to (ii), (b) to (III), (c) to (i), d to (iv)`


Discussion

No Comment Found