A uniform cylindrical rod of length L and cross-sectional area by forces as shown in figure. The elongation produced in the rod is

A uniform cylindrical rod of length L and cross-sectional area by forc

1.	A uniform cylindrical rod of length L and cross-sectional area by forces as shown in figure. The elongation produced in the rod is
Answer» `(3F L)/(8 AY)` `(3FL)/(5AY)` `(8FL)/(3AY)` `(5FL)/(3AY)` Solution :(c) ELONGATION production if the `(2)/(3)` part of length L ofrod is stretched by a force of 3F, is given by `DeltaL_(1)=(F_(1)L_(1))/(AY)=(3Fxx(2)/(3)L)/(AY)=2(FL)/(AY)` Total elongation PRODUCED in the rod is `DeltaL=DeltaL_(1)+DeltaL_(2)=2(FL)/(AY)+(2)/(3)(FL)/(AY)` `therefore DeltaL=(8)/(3)(FL)/(AY)`