A uniform cylindrical rod of length L and cross-sectional area by forces as shown in figure. The elongation produced in the rod isA. `(3F L)/(8 AY)`B. `(3FL)/(5AY)`C. `(8FL)/(3AY)`D. `(5FL)/(3AY)`

A uniform cylindrical rod of length L and cross-sectional area by forc

1.	A uniform cylindrical rod of length L and cross-sectional area by forces as shown in figure. The elongation produced in the rod isA. `(3F L)/(8 AY)`B. `(3FL)/(5AY)`C. `(8FL)/(3AY)`D. `(5FL)/(3AY)`
Answer» Correct Answer - C (c) Elongation production if the `(2)/(3)` part of length L of rod is stretched by a force of 3F, is given by `DeltaL_(1)=(F_(1)L_(1))/(AY)=(3Fxx(2)/(3)L)/(AY)=2(FL)/(AY)` Total elongation produced in the rod is `DeltaL=DeltaL_(1)+DeltaL_(2)=2(FL)/(AY)+(2)/(3)(FL)/(AY)` `therefore DeltaL=(8)/(3)(FL)/(AY)`

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A uniform cylindrical rod of length L and cross-sectional area by forces as shown in figure. The elongation produced in the rod isA. `(3F L)/(8 AY)`B. `(3FL)/(5AY)`C. `(8FL)/(3AY)`D. `(5FL)/(3AY)`

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