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A uniform disc of mass `m` & radius `R` is pivoted at its centre `O` with its plane vertical as shown in figure A circular portion of disc of radius `(R )/(2)` is removed from it. The time period of small oscillations of remaining portion about `O` is - A. `3pi sqrt((R )/(g))`B. `pi sqrt((13R)/(g))`C. `2pi sqrt((39R)/(16g))`D. `2pisqrt((7R)/(6g))` |
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Answer» Correct Answer - B A uniform ………… `T = 2pi sqrt((I)/(mgy_(cm)))` `I = (MR^(2))/(2) - ((1)/(2)(M)/(4)((R )/(2))^(2) + (M)/(4)((R )/(2))^(2))= (13MR^(2))/(32)` `y_(cm) = (R )/(6)` `T = 2pi sqrt((13)/(4) (R )/(g))` |
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