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A uniform disc of mass `m` & radius `R` is pivoted at its centre `O` with its plane vertical as shown in figure `A` circular portion of disc of radius `(R)/(2)` is removed from it. Then choose the correct option(s) A. Time period of small oscillations of remaining portion about `O` is `pisqrt((13R)/(g))`B. Time period of small oscillations of remaining portion about `O` is `2pisqrt((13R)/(g))`C. The centre of mass of the remaining disc is at a distance of `(R)/(6)` from `O`.D. The centre of mass of the remaining disc is at a distance of `(R)/(8)` from `O`. |
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Answer» Correct Answer - A::C `T = 2pisqrt((I)/(mgy_(cm)))` `t = (MR^(2))/(2) - ((1)/(2)(M)/(4)((R)/(2))^(2) + (M)/(4)((R)/(2))^(2)) = (13MR^(2))/(32)` `rArr y_(cm) = (R)/(6)` `m = (3M)/(4)c` `T = 2pi , sqrt((1)/(4)(R)/(g))` |
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