A uniform disc of radius a and mass m, is rotating freely with angular speed omega in a horizontal plane. About a smooth fixed vertical axis through its centre. A particle, also of mass m, is suddently attached to the rim of the disc of the disc and rotates with it. The new angular speed is

A uniform disc of radius a and mass m, is rotating freely with angular

1.	A uniform disc of radius a and mass m, is rotating freely with angular speed omega in a horizontal plane. About a smooth fixed vertical axis through its centre. A particle, also of mass m, is suddently attached to the rim of the disc of the disc and rotates with it. The new angular speed is
Answer» `(OMEGA)/(6)` `(omega)/(3)` `(omega)/(2)` `(omega)/(5)` SOLUTION :From the CONSERVATION of angular momentum, `I_(1)omega_(1)=I_(2)omega_(2)` `:. omega_(2)=(I_(1))/(I_(2)).omega_(1)=((1//2ma^(2)))/((1//2ma^(2))+ma^(2)).omega=(omega)/(3)`.