1.

A uniform electric field of `400 V/m` is directed at `45^@` above the x-axis as shown in the figure. The potential difference `V_A-V_B` is given by

Answer» Correct Answer - D
`E=400 cos45^@hati+400sin45^@hatj`
`V_A-V_B=-int_B^AE.dr`
where `dr=dxhati+dyhatj`


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