A uniform field of `2 kN//C` is the x direction. A point charge `= 3 mu C` initially at rest at the origin is released. What is K.E. of this charge at x = 4m ? Also, calculate `V (4m) - V (0)`.

A uniform field of `2 kN//C` is the x direction. A point charge `= 3 m

1.	A uniform field of `2 kN//C` is the x direction. A point charge `= 3 mu C` initially at rest at the origin is released. What is K.E. of this charge at x = 4m ? Also, calculate `V (4m) - V (0)`.
Answer» Correct Answer - 24xx10^(17) Vm^(-1) ; 4.5xx10^(21) Vm^(-1)` From `E = - (dV)/(dr)`, `dV = -E (dr) = -2xx10^(3) (4) = -8xx10^(3) V` Gain in K.E. = Loss in P.E. `= q (dV) = 3xx10^(3) (8xx10^(3)) = 24xx10^(-3)J`

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A uniform field of `2 kN//C` is the x direction. A point charge `= 3 mu C` initially at rest at the origin is released. What is K.E. of this charge at x = 4m ? Also, calculate `V (4m) - V (0)`.

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