A uniform horizontal metre scale of mass m is suspended by two vertical strings attached to its two ends. A body of mass 2m is placed on the 75 cm mark. The tensions in the two strings are in the ratio is

A uniform horizontal metre scale of mass m is suspended by two vertica

1.	A uniform horizontal metre scale of mass m is suspended by two vertical strings attached to its two ends. A body of mass 2m is placed on the 75 cm mark. The tensions in the two strings are in the ratio is
Answer» `1: 2` `1 : 3` `2 : 3` `3 : 4` Solution : `T_(1) + T_(2) = 3mg` TAKING TORQUES about A , we get 0.5 mg + 0.75 `xx 2 mg = 1 xx T_(1) therefore T_(2) = 2 mg` SIMILARLY , taking torque about B , we get `T_(1) = mg` `therefore (T_(1))/(T_(2)) = (1)/(2)`