1.

A uniform ladder of mass 10kg leans against a smooth vertical wall making an angle 53^(0) with it. The other end rests on a rough horizontal floor. Find the normal force and the frictional force that the floor exerts on the ladder.

Answer»

Solution :
The LADDER is in equilibrium
`:.N_(1)=f` and
`N_(2)=W`
TAKING torque about .B.
`N_(1)(AO)=W(CB)`.
or `N_(1)(AB)cos53=W((AB)/(2))sin53`
or `N_(1)=(2)/(3)W`
and `N_(2)=W=10xx9.8=98N`
The FRICTIONAL force is
`f=N_(1)=(2)/(3)W=65N`


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