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A uniform magnetic field `barB =B_(0)hatj` exists in a space. A particle of mass m and charge q is projected towards negative x-axis with speed v from the a point `(d,0,0)` The maximum value v for which the particle does not hit `y-z` plane is .A. `(Bqa)/(m)`B. `(Bqa)/(2m)`C. `(Bq)/(am)`D. `(Bq)/(2am)` |
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Answer» Correct Answer - A Here the paticle is projected in a direction perpendicular to the uniform magnetic field hence it will describe a circular path the particle will not hit the yz plane if the radius of the circular path is smaller than a for maximum value of v the radius of circular pth is just equal to a or `V=(Bqa)/(m)` |
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