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The magnetic induction at apoint P which is at the distance 4 cm from a long current carrying wire is `10^(-3) T`. The field of induction at a distance 12 cm from the current will beA. `3.33xx10^(-9)`teslaB. `1.11xx10^(-4)` teslaC. `3xx10^(-3)` teslaD. `9xx10^(-2)` tesla |
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Answer» Correct Answer - A The magnetic field `beta =(mu_(0))/(2pi)-(2i)/(r ) therefore (beta_(1))/(beta_(2))=(r_(2))/(r_(1))` `(10^(-8))/(beta_(2))=12/14 rarrbeta_(2)=3.33 xx10^(-4) T` |
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