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A uniform magnetic field of magnitude 0.20T exists in space from east to west. With what speed should a particle of mass 0.010g and having a charge 1.0 x 10-5C be projected from south to north so that it moves with a uniform velocity? |
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Answer» B = 0.20T, v = ? m = 0.010g = 10–5kg, q = 1 × 10-5C Force due to magnetic field = Gravitational force of attraction So, qvB = mg => 1 × 10–5 × v × 2 × 10–1 = 1 × 10–5 × 9.8 => v = (9.8 x 10-5)/(2 x 10-6) = 49m/s. |
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