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A uniform of mass m and length L is tied to a vertical shaft. It rotates in horizontal plane about the vertical axis at angular velocity omega. How much horizontal force does the shaft exert on the rod? |
Answer» Solution :Let `T` be the force applied horizontally on the rod. The acceleration of the centre of MASS is `omega^(2)(L/2)` as it moving in a circle of radius `L/2`. Using `vecF_(ext)=Mveca_(CM)impliesT=Momega^(2)(L/2)` THUS, the horizontal force exerted is `1/2Momega^(2)L`. |
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